Given mass of Scandium = 50.0 g
Increase in temperature of the metal when heated = [tex]61.1^{0}C[/tex]
Heat absorbed by Scandium = [tex]1.50*10^{3}J[/tex]
The equation showing the relationship between heat, mass, specific heat and temperature change:
[tex]Q = m C (deltaT)[/tex]
Where Q is heat = [tex]1.50*10^{3}J[/tex]
m is mass = 50.0 g
ΔT = [tex]61.1^{0}C[/tex]
On plugging in the values and solving for C(specific heat) we get,
[tex]1.50*10^{3}J[/tex]=50.0g(C)([tex]61.1^{0}C[/tex])
C = 0.491[tex]\frac{J}{g^{0}C }[/tex]
Specific heat of the metal = 0.491[tex]\frac{J}{g^{0}C }[/tex]
