In a car moving at constant acceleration, you travel 290 m between the instants at which the speedometer reads 40 km/h and 80 km/h . Part a part complete how many seconds does it take you to travel the 290 m ?

We know the equation of motion [tex]v^2 =u^2+2as[/tex] , where s is the displacement, u is the initial velocity, a is the acceleration and v is the final velocity.

In this case initial velocity = 40 km/h = 11.11 m/s

Final velocity = 80 km/h = 22.22 m/s

Displacement = 290 m

Substituting

[tex]22.22^2=11.11^2+2*a*290\\ \\ a = 0.64 m/s^2[/tex]

Now we have v = u+at, where t is the time taken.

Substituting

22.22 =11.11 + 0.64*t

t = 17.36 seconds

So car will take 17.36 seconds to travel the 290 meter.

asuwafohjames asuwafohjames · Answer 2 · 2022-04-12T10:39:19+02:00

The time in seconds it will take to travel the 290 m distance is 52.2 s.

To calculate the time it will take to travel 290 m, we use the formula below.

Formula:

S = (v+u)t/2............... Equation 1

Where:

S = Distance
v = Initial velocity
u = Final velocity
t = time

make t the subject of the equation

t = 2S/(v+u)............ Equation 2

From the question,

Given:

S = 290 m = 0.29 km
v = 80 km/h
u = 40 km/h

Substitute these values into equation 2

t = (2×0.29)/(80-40)
t = 0.58/40
t = 0.0145 h
t = (0.0145×3600) s
t = 52.2 seconds.

Hence, The time in seconds it will take to travel the 290 m distance is 52.2 s.

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