Two jets leave at the same time and fly in opposite directions. One is heading west 50 mph faster than the other flying east. After 2 hours they are 2500 miles apart. Find each of their speeds.

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rejkjavik rejkjavik · Answer 1 · 2018-08-22T21:00:23+02:00

Let's assume

speed of second jet is x mph

we are given

One is heading west 50 mph faster than the other flying east

so, speed of second jet is x+50

they are moving in opposite direction

now, we will find distance travelled by them after 2 hours

Distance travelled by second jet after 2 hours:

we know that

distance =speed*time

so, [tex] d_1=x*2 [/tex]

so, [tex] d_1=2x [/tex]

Distance travelled by first jet after 2 hours:

we know that

distance =speed*time

so, [tex] d_2=(x+50)*2 [/tex]

so, [tex] d_1=2x+100 [/tex]

now, we can find total distance

so, [tex] d=d_1+d_2 [/tex]

[tex] d=2x+2x+100 [/tex]

we are given that distance as 2500

so, we can set it to 2500

[tex] 2500=2x+2x+100 [/tex]

now, we can solve for x

[tex] 4x=2400 [/tex]

[tex] x=600 [/tex]

so,

speed of second jet is 600 mph

speed of first jet is 650 mph.................Answer