[tex]\dfrac{16\,\mathrm{km}}{1\,\mathrm h}\cdot\dfrac{8\,\mathrm h}{1\,\mathrm d}=128\,\dfrac{\mathrm{km}}{\mathrm d}[/tex]
So if the cyclist travels on average 128 km each day, then it will take
[tex]800\,\mathrm {km}\cdot\dfrac{1\,\mathrm d}{128\,\mathrm {km}}=6.25\,\mathrm d[/tex]
