Respuesta :

altavistard

One simple approach would be to choose an x value, such as x = 8, calculate y using the given formula, and then choosing the graph that shows a C(t) value closer to your calculated value.


Please evaluate C(8).

DeanR

Let's plug in a couple of a values for t and match them up against the graphs.


[tex] C(t) = 50000 (0.9)^t - 2000 [/tex]


[tex] C(0) = 50000-2000=48000[/tex]


[tex]C(1) = 50000(.9)-2000 = 43000[/tex]


[tex]C(2) = 50000(.9)^2-2000=50000(.81) -2000 = 38500[/tex]


[tex]C(8) = 50000(.9)^8-2000 \approx 19523[/tex]


[tex]C(20) = 50000(.9)^8-2000 \approx 4079[/tex]


Look for


(0,48000), (1,43000), (2,38500),(8,19523),(20,4079)


A. C(8) is way off


B C(0) isn't exactly 48000 like A and C


C. C(0) matches, C(8) matches, C(20) matches, SELECT CHOICE C


D. C(0) and C(20) are off.


Choice C



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