The correct answer is the first option.
If you want to use elimination, you can sum the two equations for example, so that the x's simplify:
[tex] (-2x+4y)+(2x+2y) = 16+8 [/tex]
[tex] 6y = 24 [/tex]
[tex] y = 4 [/tex]
Plug this value for y in one of the equations to derive the value of x:
[tex] 2x+2y=8 \implies 2x + 8 = 8 \implies x = 0 [/tex]
So, the solution is [tex] (x,y) = (0,4) [/tex]
