G find the standard form of the equation of the parabola satisfying the given conditions. ​focus: left parenthesis negative 5 comma 6 right parenthesis​; ​directrix: y equals 2

Respuesta :

The focus is above the directrix 4 units (the difference between y=2 and y=6), so you know the parabola opens upward. The distance from either to the vertex is half that, or 2 units. If you call this distance p, the equation of the parabola with vertex (h, k) can be written as

... y = 1/(4p) × (x-h)² +k


In some parts of the world, this is the form referred to as "standard form." Filling in the numbers p = 2, (h, k) = (-5, 4), this is

... y = (1/8)(x +5)² +4


Elsewhere, "standard form" has this multiplied out.

... y = (1/8)x² + (5/4)x + 57/8



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Multiplying out (x+a)² gives x² +2ax +a².

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Answer:

dee um quadratic graphs and their properties quick check tingz

1. C ,->(1,-4)

2. B -> (y=0.5^2+1)

3. D -> (the graph that goes like down and has -4)

4. A -> (f(x) = –10x², f(x) = 2x², f(x) = 0.5x²)

Step-by-step explanation:

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