emmi1699
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A 15.6 g sample of ethyl alcohol absorbs 0.207 kcal of energy as it is heated. If the initial temperature of the ethanol was 21.5 °C, what is the final temperature of the ethanol? (cethanol = 0.58 kcal/kg °C)


22.9 ° C
25.0 ° C
44.4 ° C

Respuesta :

m = mass of sample = 15.6 g = 0.0156 kg

c = specific heat of the sample = 0.58 kcal/kgC = 580 cal/(kgC)

[tex] T_{i} [/tex] = initial temperature = 21.5 C

[tex] T_{f} [/tex] = final temperature = ?

Q = heat absorbed = 0.207 kcal = 207 cal

using the equation

Q = m c ([tex] T_{f} [/tex]-[tex] T_{i} [/tex])

207 = (0.0156) (580) ([tex] T_{f} [/tex]-21.5)

[tex] T_{f} [/tex] = 44.4

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