Respuesta :

DeanR

Half the entries have an even number first; half of those have an odd number second, so


[tex]p = \dfrac 1 4[/tex]


second choice

Let's eliminate our options and then check.

Since 1, 3, and 5 are odd numbers, there's a 50% chance for and then it gets reduced to a 25% chance due to the second number have to be odd.

This means that 9 of the pairs will have an even number, odd number duo.

The pairs are:

2,1

2,3

2,5

4,1

4,3

4,5

6,1

6,3

6,5


So, B. 1/4