If the diameter of sphere is reduced by half, its surface becomes A. one-quarter the original surface. B. double the original surface. C. half the original surface. D. four times the original surface.
Surface area is 4*pie*r^2 If the diameter is reduced by half, radius is reduced by half New radius is r’ r’ = r/2 So new area = 4*pie*r’^2 = pie * r^2 So A
