Respuesta :
2x^2 − 12xy − 32y^2
= 2(x^2 - 6xy - 16y^2)
= 2(x - 8y)(x + 2y)
Answer
B = 2
Answer:
The value of B is 2.
Step-by-step explanation:
The given trinomial is
[tex]2x^2-12xy-32y^2[/tex]
Taking out the GCF.
[tex]2(x^2-6xy-16y^2)[/tex]
The middle term can be written as -8xy+2xy.
[tex]2(x^2-8xy+2xy-16y^2)[/tex]
[tex]2(x(x-8y)+2y(x-8y))[/tex]
[tex]2(x-8y)(x+2y)[/tex]
The factored form of the given trinomial is 2(x-8y)(x+2y). The given factored form of the trinomial is 2(x − 8y)(x + By). Equate both factored form.
[tex]2(x-8y)(x+2y)=2(x-8y)(x+By)[/tex]
On comparing both the sides we get
[tex]B=2[/tex]
Therefore the value of B is 2.