It would help to have the question. But I'll guess
[tex]\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}} = ((x^{\frac 3 5})^{\frac 1 4}) }{ x} = x^{\frac 3{20}} x = x \sqrt[20]{x^3}[/tex]
2nd choice.
I forgot the explanation because I was so glad to have puzzled out the question.
The fourth root is the same as the 1/4 th power.
If we know x is positive [tex]\sqrt{x^2}=|x|=x[/tex]
[tex]\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}}[/tex]
[tex] = ((x^{\frac 3 5})^{\frac 1 4}) }{ x}[/tex]
We multiply the powers: [tex](a^b)^c=a^{bc}[/tex]
[tex]= x^{\frac 3{20}} x[/tex]
The one-twentieth power is the twentieth root. We bring the additional factor of x to the front.
[tex]= x \sqrt[20]{x^3}[/tex]
