Respuesta :

JonHenderson55

The correct answer is: " 10 " .

___________________________________________

→ " f(-3) = 10 " .

___________________________________________

Explanation:

___________________________________________


Given:

___________________________________________


f(x) = 7 − x ; if: x ≤ -3 ;


f(x) = x + 4 ; if: x > -3 ;

_________________________________________


Find: " f(-3) " :

_________________________________________


Note:  " f(x) = f(-3) " ;  → " x = - 3 " ;


Since  " x  = -  =3 " ;   →  x is NOT greater than "-3" ;


→ So; " f(x) does NOT equal " x + 4" ;

_________________________________________

Consider our other option given:


We have "x = -3 " .


We our given: If " x ≤ -3 " ; {that is; if "x" is less than or equal to "-3" };


→  then: " f(x) =  7 −  x " .

______________________________________________


Since: " x = - 3 " ;


→ then " x ≤ -3 " ;  and:


→ f(x) = 7 − x  ;


THEN:


→ f(-3) = 7 − (-3) ;  →  Note:  Plug in "-3" for the value(s) of "x" in the equation;

and solve:

→         =  7  +  3 ;    

             =  10 .

___________________________________________________

→  f(-3)  =  10  .


_____________________________________

The answer is:  " 10 " .

_____________________________________

Hope this answer — and explanation — is helpful to you.

Best wishes in your academic pursuits!

_____________________________________

facundo3141592

Here we have a piecewise function.

A piecewise function is a function that behaves differently in different intervals.

We will find that the solution is F(-3) = 10

Our particular function is:

F(x) = 7 - x     if   x ≤ -3

F(x) = x + 4    if  x  > -3

So to evaluate F(x) in a particular value of x = a, the first thing we need to do is see in which interval does the value a belong.

Here we want to get F(-3), so we have a = -3

Notice that the element -3 is a solution of x ≤ -3, then we should use the above function:

F(-3) = 7 - (-3) = 7 + 3 = 10

F(-3) = 10

If you want to learn more, you can read:

https://brainly.com/question/12561612

Otras preguntas