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Solve for x.

−ax + 4b > 9



1) x > the quantity 4 times b minus 9 all over a

2) x < the quantity 9 minus 4 times b all over a

3) x < the quantity negative 4 times b plus 9 all over negative a

4) x > the quantity 4 times b plus 9 all over negative a

Respuesta :

carlosego

The answer is the first option: 1) [tex] x [/tex]> the quantity [tex] 4 [/tex] times [tex] b [/tex] minus [tex] 9 [/tex] all over [tex] a [/tex]

The explanation is shown below:

1. To solve this problem you must pply the following proccedure:

2. Move the term[tex] 4b [/tex] to the left member. As the variable is negative, multiply the expression by[tex] -1 [/tex] and change the direction of the sign:

[tex] -ax+4b>9\\ (-1) -ax>9-b4 (-1)\\ x>\frac{ab-9}{a} [/tex]

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