Aluminum reacts with aqueous copper (II) chloride in a single displacement reaction to produce aluminum chloride and solid copper. How many moles of copper (II) chloride are required to react fully with 0.357 mol aluminum?

Respuesta :

2Al + 3CuCl2 ------> 3Cu + 2AlCl3

from reaction 2 mol 3 mol

given 0.357 mol x mol


x= 0.375*3/2 = 0.563 mol CuCl2