The first thing we must do for this case is to find the equation of the line.
[tex]y-yo = m (x-xo)
[/tex]
We have then:
[tex]m = (y2 - y1) / (x2-x1)
m = (-3 - 0) / (2-8)
m = 1/2[/tex]
We choose an ordered pair:
[tex](xo, yo) = (8, 0)
[/tex]
Substituting values:
[tex]y-0 = (1/2) (x-8)
y = (1/2) x - 4[/tex]
From here we conclude:
Intersection with y:
We evaluate x = 0 in the function:
[tex]y = (1/2) (0) - 4
y = -4[/tex]
Slope of the line:
[tex]m = 1/2
[/tex]
Point (-2, -5):
We evaluate the value of x = -2 and the value of y = -5
[tex]-5 = (1/2) (- 2) - 4
-5 = -1 - 4
-5 = - 5[/tex]
The equation is satisfied.
Point (8, 0):
It is part of the table, therefore belongs to the line.
Answer:
The slope is 1/2
The y-intercept is -4.
The points (-2, -5) and (8, 0) are also on the line.
