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Suppose that a single die with 7 sides (numbered 1, 2, 3, ... , 7) is rolled twice. what is the probability that the sum of the two rolls equals 6 ?

Respuesta :

gmany
[tex]\Omega=\{(1;1);\ (1;2);\ (1;3);\ ...;\ (7;6);\ (7;7)\}\\\\|\Omega|=7^2=49[/tex]

[tex]A=\{(1;\ 5);\ (2;\ 4);\ (3; 3);\ (4;\ 2);\ (5;\ 1)\}\\\\|A|=5[/tex]

[tex]\boxed{P(A)=\dfrac{5}{49}}[/tex]

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