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A bicyclist was moving at a rate of 8 m/s, and then sped up to 10 m/s. If the cyclist has a mass of 120 kg, how much work was needed to increase his velocity? (Hint: Use the work-kinetic energy theorem.)

Respuesta :

Answer:

Work = 2160 J

Explanation:

As per work energy theorem we know that work done is equal to the change in the kinetic energy of the cyclist.

As the cyclist is initially moving at speed 8 m/s and after some time his speed changes to 10 m/s

So here we can say that

final kinetic energy - initial kinetic energy = work done

[tex]W = \frac{1}{2}m(v_f^2 - v_i^2)[/tex]

now by plug in all values

[tex]W = \frac{1}{2}(120)(10^2 - 8^2)[/tex]

[tex]W = 2160 J[/tex]

so work done by cyclist will be 2160 J

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