Respuesta :
The graph of this function is shown in the figure below. The general form of a sine wave is given by:
[tex]y(t)=Asin(2 \pi ft+\Phi)+B[/tex]
A: The amplitude.
f : The ordinary frequency, the number of oscillations (cycles) that occur each second of time.
ω = 2πf, the angular frequency, the rate of change of the function argument in units of radians per second
B = the displacement in y-axis
[tex]\Phi[/tex] = the phase, specifies (in radians) where in its cycle the oscillation is at t = 0.
The period is given by:
[tex]T= \frac{1}{f}[/tex]
Therefore:
[tex]\omega= \frac{2 \pi }{T}[/tex]
And givent that [tex]\omega= 1[/tex], then [tex]T=2\pi[/tex],
Finally, the starting point for a sample period occurrs when [tex]t=0[/tex]
[tex]f(0)=0.2sin(0-0.3)+0.1=\boxed{0.04}[/tex]
[tex]y(t)=Asin(2 \pi ft+\Phi)+B[/tex]
A: The amplitude.
f : The ordinary frequency, the number of oscillations (cycles) that occur each second of time.
ω = 2πf, the angular frequency, the rate of change of the function argument in units of radians per second
B = the displacement in y-axis
[tex]\Phi[/tex] = the phase, specifies (in radians) where in its cycle the oscillation is at t = 0.
The period is given by:
[tex]T= \frac{1}{f}[/tex]
Therefore:
[tex]\omega= \frac{2 \pi }{T}[/tex]
And givent that [tex]\omega= 1[/tex], then [tex]T=2\pi[/tex],
Finally, the starting point for a sample period occurrs when [tex]t=0[/tex]
[tex]f(0)=0.2sin(0-0.3)+0.1=\boxed{0.04}[/tex]
