1) Speed acquired
The time taken for the motion is
[tex]t=2 min=2 \cdot 60 = 120 s[/tex]
The bus is moving by uniformly accelerated motion, with constant acceleration [tex]a=0.1 m/s^2[/tex], so the speed acquired by the bus after 120 s is
[tex]v(t) = at=(0.1 m/s^2)(120 s)=12 m/s[/tex]
2) The distance traveled is given by the following formula:
[tex]S= \frac{1}{2}at^2 [/tex]
where a is the acceleration and t the time. Substituting numbers into the equation, we find
[tex]S= \frac{1}{2}(0.1 m/s^2)(120 s)^2=720 m [/tex]
