Respuesta :
Answer: 170.6°Z
Explanation:
1) Since you are given two pair of points, you have to assume a linear relation ship to find the new scale.
2) Boiling point of nitrogen is -195.8° C and 0° Z
⇒ (- 195.8, 0)
3) Melting point of iron is 1538° C and 1000° Z
⇒ (1538, 1000)
4) Find the linear equation between C and Z:
[tex] \frac{1000 - 0}{1538-(-195.8)} = \frac{Z-0}{C-(-195.8)} [/tex]
Solving for Z:
1000 (C + 195.8) = Z (1538 + 195.8) ⇒
1000 C + 195,800 = 1,733.8Z ⇒
Z = (1,000/1,733.8)C + 195,800/1,733.8
4) Boiling point of water is 100°C ⇒ replace C = 100 in the equation
Z = (1,000 / 1733.8) (100) + 195,800/1,733.8 = 170.6°Z
Explanation:
1) Since you are given two pair of points, you have to assume a linear relation ship to find the new scale.
2) Boiling point of nitrogen is -195.8° C and 0° Z
⇒ (- 195.8, 0)
3) Melting point of iron is 1538° C and 1000° Z
⇒ (1538, 1000)
4) Find the linear equation between C and Z:
[tex] \frac{1000 - 0}{1538-(-195.8)} = \frac{Z-0}{C-(-195.8)} [/tex]
Solving for Z:
1000 (C + 195.8) = Z (1538 + 195.8) ⇒
1000 C + 195,800 = 1,733.8Z ⇒
Z = (1,000/1,733.8)C + 195,800/1,733.8
4) Boiling point of water is 100°C ⇒ replace C = 100 in the equation
Z = (1,000 / 1733.8) (100) + 195,800/1,733.8 = 170.6°Z
The boiling point of water on the z scale is mathematically given as
Z= 170.6°Z
What is the boiling point of water on the z scale?
Question Parameter(s):
the boiling point of nitrogen 0 ∘z and the melting point of iron 1000 ∘z
Generally, the equation for the relationship between C and Z is mathematically given as
[tex]\frac{1000 - 0}{1538-(-195.8)} = \frac{Z-0}{C-(-195.8)}[/tex]
Therefore
1000 (C + 195.8) = Z (1538 + 195.8)
1000 C + 195,800 = 1,733.8Z
Z = (1,000/1,733.8)C + 195,800/1,733.8
In conclusion, with boiling point of water as 100°C
Z = (1,000 / 1733.8) (100) + 195,800/1,733.8
Z= 170.6°Z
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