The engineer weighed two pieces of metal for an experiment. The piece of iron weighed 5 1⁄4 pounds and the piece of aluminum weighed 1 7⁄8 pounds. How much more did the piece of iron weigh than the piece of aluminum?

Respuesta :

The piece of iron weighed 5 1⁄4 pounds and the piece of aluminum weighed 1 7⁄8 pounds.

So the answer is 5 1⁄4 - 1 7⁄8 = 3 3/8 pounds.


kanest
Convert the mixed numbers into fractions.

[tex]5 \frac{1}{4} [/tex]
[tex]5 * 4 = 20[/tex]
[tex]20 + 1 = 21[/tex]
[tex]5 \frac{1}{4} = \frac{21}{4}[/tex]

[tex]1 \frac{7}{8} [/tex]
[tex]1 * 8 = 8[/tex]
[tex]8 + 7 = 15[/tex]
[tex]1 \frac{7}{8} = \frac{15}{8} [/tex]

Because both fractions have different denominators, we have to change one fraction so that its denominator will match. We will take 21/4 and multiply both the numerator and denominator by 2 so that it will match the denominator of 15/8:

[tex] \frac{21}{4} * \frac{2}{2} = \frac{42}{8} [/tex]

Now we can subtract 42/8 by 15/8:

[tex]\frac{42}{8} - \frac{15}{8} = \frac{27}{8}[/tex]

Convert the fraction back into a mixed number:

[tex]27 / 8 = 3 R3 = 3 \frac{3}{8} [/tex]

The piece of iron weighted 3 and three-eighths pounds more than the piece of aluminum.