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At a baseball game, the probability that a fan brings a glove is 0.08. The probability that a fan is left-handed is 0.12. What is the probability that a randomly selected fan has a baseball glove and is left-handed? Round your answer to the nearest hundredth, if necessary.

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sqdancefan
If the probabilities are independent, the probability that a left-handed person will bring a glove is ...
  0.08×0.12 = 0.0096 ≈ 0.01

Let [tex] A [/tex] and [tex] B [/tex] be two events. Then

[tex] P(A \cup B)=P(A)P(B) [/tex].If the events are independent. Here

Let [tex] A=\{a\; fan \;brings\; a \;glove\},B=\{a\; fan \;is\; a \;left-handed\} [/tex].

Then, the probability that a randomly selected fan has a baseball glove and is left-handed is

[tex] P(A \cup B)=0.08*0.12=0.0096 [/tex]

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