Read the proof. Given: AEEC; BDDC Prove: △AEC ~ △BDC Triangle A E C is shown. Line segment B D is drawn near point C to form triangle B D C. Statement Reason 1. AEEC;BDDC 1. given 2. ∠AEC is a rt. ∠; ∠BDC is a rt. ∠ 2. definition of perpendicular 3. ∠AEC ≅ ∠BDC 3. all right angles are congruent 4. ? 4. reflexive property 5. △AEC ~ △BDC 5. AA similarity theorem What is the missing statement in step 4? ∠ACE ≅ ∠BCD ∠EAB ≅ ∠DBC ∠EAC ≅ ∠EAC ∠CBD ≅ ∠DBC