Which equation is y=-6 x^2+3 x+2 rewritten in vertex form?
$y=-6(x-1)^2+8
$y=-6\left(x+\frac{1}{4}\right)^2+\frac{13}{8}$
$y=-6\left(x-\frac{1}{4}\right)^2+\frac{19}{8}$
$y=-6\left(x-\frac{1}{2}\right)^2+\frac{7}{2}$