In the formula below, P represents the electric power of a light bulb measured in watts, Vis the voltage, and / is the current in
amperes.
P = VI
A 60-watt light bulb has a current of 4 amperes and a voltage of 15 volts.
If the voltage of the 60-watt light bulb doubles, what will happen to the current?
A. The current will decrease by one-fourth
B. The current will decrease by half.
C. The current will stay the same.
D. The current will double.